The potential energy of interaction of two nucleons at

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The potential energy of interaction of two nucleons at a distance r from each other is well described by the Japanese physicist Yukawa: U (r) = (r0 / r) U0exp (-r / r0), where U0 = 50 MeV, and r0 = 1,5 * 10 ^ -15 m. Find the expression for the corresponding force F (r). How many times will decrease the force with increasing distance between the nucleons of the value of r1 = r0 to a value of r2 = 4r0?

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Task 10965. Detailed solution with a short recording conditions, laws and formulas used in the decision, the withdrawal of the calculation formula and the answer.
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