Mokhovikov a solid disc, the moment of inertia

Affiliates: 0,02 $how to earn
Pay with:
i agree with "Terms for Customers"
Sold: 3
Refunds: 0

Uploaded: 24.01.2014
Content: 10165.tif (32,75 kB)
Loyalty discount! If the total amount of your purchases from the seller Юрий Физик more than:
5 $the discount is30%
1 $the discount is10%
If you want to know your discount rate, please provide your email:


Mokhovikov a solid disc, the moment of inertia is J = 1,5 kg * m2 rotating when braking ravnozamedlenno for time t = 1 min reduced the frequency of their rotation with n1 = 240 rev / min to n2 = 120 rev / min. To determine: 1) the angular acceleration of the flywheel; 2) the time of braking forces; 3) A brake job

Additional information

Task 10165. Detailed solution shorthand terms, formulas, laws used in the decision, the withdrawal of the calculation formula and the response.


No feedback yet.
1 month 3 months 12 months
0 0 0
0 0 0
In order to counter copyright infringement and property rights, we ask you to immediately inform us at the fact of such violations and to provide us with reliable information confirming your copyrights or rights of ownership. Email must contain your contact information (name, phone number, etc.)