Diatomic gas at a pressure of 1200 kPa p1 = the volume

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Uploaded: 04.07.2014
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Description

Diatomic gas at a pressure of 1200 kPa p1 = volume has V1 = 0,18 m ^ 3, at a pressure of 850 kPa p2 = - volume V2 = 0,42 m ^ 3. The transition from the first state to the second was done in two stages: first by the isotherm, and then isochor. The amount of heat absorbed by the gas Q, the increase of internal energy. To determine gas job A.

Additional information

Task 20475. Detailed solution shorthand terms, formulas and laws used in the decision, the withdrawal of the calculation formula and the response.
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