DHS 15.1 - Option 21. Decisions Ryabushko AP

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Uploaded: 09.11.2016
Content: 21v-IDZ15.1.doc (217 kB)

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1. Dana function u (M) = u (x, y, z) and the point M1, M2. Calculate: 1) The derivative of this function in the direction of the point M1 M1M2 vector; 2) grad u (M1)

1.21. u (M) = xyz, M1 (3, 1, 4), M2 (1, -1, -1)

2. Calculate the surface integral of the first kind on the surface S, where S - part of the plane (p), cut off by the coordinate planes.

 (P): x + 2y + 2z = 4

3. Calculate the surface integral of the second kind.

 where S - the inner side of the cylinder x2 + y2 = 4, cut off by the plane z = 0 and z = 1

4. Calculate the flow vector field a (M) through the outer surface of the pyramid formed by plane (p) and the coordinate planes in two ways: a) determination using flow; b) using the formula Ostrogradskii - Gauss.

4.21. and (M) = (2z - x) i + (x - y) j + (3x + z) k, (p): x + y + 2z = 2

Additional information

Detailed solution. Decorated in Microsoft Word 2003 (Quest decided to use the formula editor)

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