88. Determine the smallest thickness of the crystal pla

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88. Determine the smallest thickness of the crystal plate a quarter wavelength for λ = 530 nm, if the difference in the refractive indices of the ordinary and extraordinary rays for a given wavelength ne - no = 0,01. A quarter wave plate called crystal plate cut parallel to the optical axis, through which passes in a direction perpendicular to the optical axis, the ordinary and extraordinary beams without changing their direction, become the path difference equal to λ / 4.

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Detailed solution. Decorated in Microsoft Word 2003. (Target decided to use formula editor)


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