76. In the nuclear reaction 21H + 21H → 32He + 10

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76. In the nuclear reaction 21H + 21H → 32He + 10n releases energy ΔE = 3,27MeV. Determine the mass of the atom 32He, if the mass of 2.01410 amu is 21H

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Detailed solution. Decorated in Microsoft Word 2003. (Target decided to use formula editor)


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